Practice question

**Resistor in AC** behaves as DC, no reactance, impedance Z=R, current follows voltage exactly, average power over cycle V_rms I_rms, for 200 V rms, 80 Ω, P=500 W? Actually 200²/80=500 W, peak current √2×2.5=3.535 A, average power ½ V_peak I_peak. In an RL series circuit, the phase angle Φ = tan⁻¹ ( (X_L/R) ) . The magnitude of this angle depends on the ratio of inductive reactance ( X_L = ω L ) to resistance ( R ), as it reflects the relative contributions of inductance and resistance. Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms = V_rms/Z,