#potential energy change

Escape Velocity and Bound Systems

A 7kg mass is moved from 7RE to 14RE from Earth’s center. What is the change in potential energy? (ME\=6×1024kg,RE\=6.4×

ΔV = −GMEm(1r2−1r1). r1 = 4.48×107m, r2 = 8.96×107m. ΔV = −6.67×10−11×6×1024×7(18.96×107−14.48×107). ΔV = −2.801×1015(−1.116×10−8)≈3.13×107J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.1 × 10⁷ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Orbital Velocity and Time Period

A 8kg mass is moved from 8RE to 16RE from Earth’s center. What is the change in potential energy? (ME\=6×1024kg,RE\=6.4×

ΔV = −GMEm(1r2−1r1). r1 = 5.12×107m, r2 = 1.024×108m. ΔV = −6.67×10−11×6×1024×8(11.024×108−15.12×107). ΔV = −3.202×1015(−9.766×10−9)≈3.13×107J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.1 × 10⁷ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Potential Energy of Mass Systems

A 9kg mass is moved from 9RE to 18RE from Earth’s center. What is the change in potential energy? (ME\=6×1024kg,RE\=6.4×

ΔV = −GMEm(1r2−1r1). r1 = 5.76×107m, r2 = 1.152×108m. ΔV = −6.67×10−11×6×1024×9(11.152×108−15.76×107). ΔV = −3.602×1015(−8.681×10−9)≈3.13×107J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.1 × 10⁷ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Variation of g with Height and Depth

A 4kg mass is moved from 3RE to 6RE from Earth’s center. What is the change in potential energy? (ME\=6×1024kg,RE\=6.4×1

ΔV = −GMEm(1r2−1r1). r1 = 1.92×107m, r2 = 3.84×107m. ΔV = −6.67×10−11×6×1024×4(13.84×107−11.92×107). ΔV = −1.601×1015(−2.604×10−8)≈4.17×107J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.2 × 10⁷ J. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Universal Law of Gravitation

A 6kg mass is moved from 6RE to 12RE from Earth’s center. What is the change in potential energy? (ME\=6×1024kg,RE\=6.4×

ΔV = −GMEm(1r2−1r1). r1 = 3.84×107m, r2 = 7.68×107m. ΔV = −6.67×10−11×6×1024×6(17.68×107−13.84×107). ΔV = −2.401×1015(−1.302×10−8)≈3.13×107J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.1 × 10⁷ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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