Practice question
Question
A 4kg mass is moved from 3RE to 6RE from Earth’s center. What is the change in potential energy? (ME\=6×1024kg,RE\=6.4×106m,G\=6.67×10−11N m2/kg2)
Explanation
ΔV = −GMEm(1r2−1r1). r1 = 1.92×107m, r2 = 3.84×107m. ΔV = −6.67×10−11×6×1024×4(13.84×107−11.92×107). ΔV = −1.601×1015(−2.604×10−8)≈4.17×107J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.2 × 10⁷ J. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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