#net force

Gravitational Effects and Applications

Three masses of 4kg each are at the vertices of an equilateral triangle with side 3m. What is the net force on one mass?

Force between two masses: F = Gm1m2r2 = 6.67×10−114×432 = 1.185×10−10N. Two forces act at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (1.185×10−10)2(1+1+1) = 1.185×10−103. FR≈2.05×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.2 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Escape Velocity and Bound Systems

Three masses of 12kg each form an equilateral triangle with side 9m. What is the net force on one mass? (G\=6.67×10−11N

Force between two masses: F = Gm2r2 = 6.67×10−1112×1292 = 1.185×10−10N. Two forces at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (1.185×10−10)2(1+1+1) = 1.185×10−103. FR≈2.05×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.1 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Work, Energy and Orbital Mechanics

Three masses of 15kg each form an equilateral triangle with side 10m. What is the net force on one mass? (G\=6.67×10−11N

Force between two masses: F = Gm2r2 = 6.67×10−1115×15102 = 1.50×10−10N. Two forces at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (1.50×10−10)2(1+1+1) = 1.50×10−103. FR≈2.60×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.6 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Gravitational Potential and Field

Three masses of 10kg each form an equilateral triangle with side 7m. What is the net force on one mass? (G\=6.67×10−11N

Force between two masses: F = Gm2r2 = 6.67×10−1110×1072 = 1.36×10−10N. Two forces at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (1.36×10−10)2(1+1+1) = 1.36×10−103. FR≈2.36×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Motion in a Plane and Projectile Motion

In uniform circular motion, what is true about the net force acting on the object?

Velocity v=v₀+at. Starting from rest, v=at. With a=(ax i+ay j), magnitude |v|=t√(ax²+ay²) per NCERT vector addition. Substituting ax, ay, t gives |v| equal to It varies in direction. Hence option C is correct.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Motion in a Plane and Projectile Motion

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