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#molecular formula

31 public questions tagged with this topic.

A compound has an empirical formula C₄H₉ and a molar mass of 114 g/mol. What is its molecular formula? (Atomic masses: C

Given: A compound has an empirical formula C₄H₉ and a molar mass of 114 g/mol. What is its molecular formula? (Atomic masses: C = 12, H = 1) Formula: Empirical mass = (4 × 12) + (9 × 1) = 48 + 9 = 57 g/mol. Substitution & Calculation: n = 114 / 57 = 2. Molecular formula = C₈H₁₈. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

A compound has an empirical formula C₂H₃O₂ and a molar mass of 118 g/mol. What is its molecular formula? (Atomic m

Given: A compound has an empirical formula C₂H₃O₂ and a molar mass of 118 g/mol. What is its molecular formula? (Atomic masses: C = 12, H = 1, O = 16) These values define the system as per NCERT data. Formula: Empirical mass = (2 × 12) + (3 × 1) + (2 × 16) = 24 + 3 + 32 = 59 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: n = 118 / 59 = 2. Molecular formula = C₄H₆O₄. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

A compound has an empirical formula CHâ‚‚O and a molar mass of 60 g/mol. What is its molecular formula? (Atomic masses:

Given: A compound has an empirical formula CH₂O and a molar mass of 60 g/mol. What is its molecular formula? (Atomic masses: C = 12, H = 1, O = 16) These values define the system as per NCERT data. Formula: Empirical mass = 12 + 2 + 16 = 30 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: n = 60 / 30 = 2. Molecular formula = C₂H₄O₂. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

In the estimation of carbon and hydrogen, 0.18 g of a compound gave 0.528 g of CO₂ and 0.108 g of H₂O. What is the empir

Mass of C = (12/44) × 0.528 = 0.144 g. Mass of H = (2/18) × 0.108 = 0.012 g. Ratio C:H = (0.144/12)/(0.012/1) = 1:1. Empirical formula = CH.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Isomerism - Structural Isomerism - Chain Position Functional Metamerism

A hydrocarbon with 9 σ bonds produces 5 moles of CO₂ per mole upon combustion. What is its molecular formula?

5 carbons (from 5 CO₂). CH₃CH₂CH₂CH₂CH₃ (pentane) has 9 σ (8 C-H, 1 C-C from single bonds), no π, and fits C₅H₁₂.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Fundamental Concepts - Reaction Mechanism - Fission and Reaction Intermediates

A hydrocarbon with a degree of unsaturation of 2 produces 4 moles of CO₂ per mole upon complete combustion. What is its

4 carbons (from 4 CO₂). Degree of unsaturation = 2 suggests two double bonds or one triple bond. CH₃C≡CCH₃ (but-2-yne, C₄H₆) fits with 2 π, 8 σ, and 4 CO₂.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance

A 0.98 g sample of a hydrocarbon produces 3.08 g of CO₂ and 1.26 g of H₂O on complete combustion. What is its molecular

Mass of C ≈ 0.84 g; mass of H = 0.14 g. Total = 0.98 g. Moles: C = 0.07, H = 0.14; ratio = 1 : 2; empirical formula = CH₂, mass = 14 g/mol. n = 98/14 = 7; molecular formula = C₇H₁₄.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition