Practice question
Question
In the estimation of carbon and hydrogen, 0.18 g of a compound gave 0.528 g of CO₂ and 0.108 g of H₂O. What is the empirical formula?
Explanation
Mass of C = (12/44) × 0.528 = 0.144 g. Mass of H = (2/18) × 0.108 = 0.012 g. Ratio C:H = (0.144/12)/(0.012/1) = 1:1. Empirical formula = CH.
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