#mass percentage

Types of Solutions and Expressing Concentration

What is the mass percentage of a solution if 5 g of a solute is dissolved in 45 g of water?

Total mass = 5 g + 45 g = 50 g. Mass % = (5/50) × 100 = 10% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration

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Types of Solutions and Expressing Concentration

What is the mass percentage of a solution if 20 g of a solute is dissolved in 180 g of water?

Total mass = 20 + 180 = 200 g . Mass % = (20/200) × 100 = 10% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration

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Types of Solutions and Expressing Concentration

A solution contains 10 g of a solute in 90 g of water. What is the mass percentage of the solute?

Total mass = 10 g + 90 g = 100 g. Mass % = (10/100) × 100 = 10% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration

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Solubility - of Solids and Gases in Liquids Henry's Law

A 0.4 M solution of KNO₃ (molar mass = 101 g/mol) has a density of 1.1 g/mL. What is the mass percentage of KNO₃ in 250

Moles = 0.4 × 0.25 = 0.1 mol . Mass of KNO₃ = 0.1 × 101 = 10.1 g . Total mass = 250 × 1.1 = 275 g . Mass % = (10.1/275) × 100 ≈ 3.673% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

What is the mass percentage of a solution prepared by dissolving 40 g of salt in 160 g of water?

Total mass = 40 + 160 = 200 g . Mass % = (40/200) × 100 = 20% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

A solution contains 25 g of a solute in 75 g of water. If the mass percentage of the solute is reduced to 20% by adding

Initial mass % = (25/25 + 75) × 100 = 25% . New mass % = 20% = (25/25 + 75 + w) × 100 . 0.2 (100 + w) = 25 , 100 + w = 125 , w = 25 g . Total mass = 100 + 25 = 125 g .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

A solution is made by dissolving 20 g of a solute in 80 g of water. If the mass percentage of the solute is doubled in a

Initial mass % = (20/20 + 80) × 100 = 20% . New mass % = 40% = (20/20 + w) × 100 . 0.4 (20 + w) = 20 , 20 + w = 50 , w = 30 g .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

What is the mass percentage of a solution prepared by dissolving 25 g of sugar in 75 g of water?

Total mass of solution = 25 g + 75 g = 100 g. Mass % = (Mass of solute/Total mass) × 100 = (25/100) × 100 = 25% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

What is the mass percentage of a solution if 25 g of a solute is dissolved in 225 g of water?

Total mass = 25 + 225 = 250 g . Mass % = (25/250) × 100 = 10% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Abnormal Molar Masses and van't Hoff Factor

What is the mass percentage of a solution prepared by dissolving 15 g of a solute in 85 g of water?

Total mass = 15 + 85 = 100 g . Mass % = (15/100) × 100 = 15% .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor

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Abnormal Molar Masses and van't Hoff Factor

A solution contains 30 g of a solute in 120 g of water. If the mass percentage of the solute is increased to 25% by evap

Initial mass % = (30/30 + 120) × 100 = 20% . New mass % = 25% = (30/30 + w) × 100 . 0.25 (30 + w) = 30 , 30 + w = 120 , w = 90 g .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor

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Abnormal Molar Masses and van't Hoff Factor

A solution contains 20 g of a solute in 80 g of solvent. If the mass percentage is 20%, what is the mass of the solution

Total mass = 20 g + 80 g = 100 g. Mass % = (20/100) × 100 = 20% , which matches the given value.

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor

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