Skip to content

Question

A solution is made by dissolving 20 g of a solute in 80 g of water. If the mass percentage of the solute is doubled in a new solution with the same solute mass, what is the mass of water required?

Options

Choose one · Correct answer highlighted

Explanation

Initial mass % = (20/20 + 80) × 100 = 20% . New mass % = 40% = (20/20 + w) × 100 . 0.4 (20 + w) = 20 , 20 + w = 50 , w = 30 g .

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.