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#magnet splitting

2 public questions tagged with this topic.

Magnetic Field Due to Bar Magnet - Axial and Equatorial

A bar magnet with original \( m = 2.8 \, \text{A m}^2 \) is cut transversely into two equal parts. What is \( m \) of ea

**Axial versus equatorial** field comparison shows B_axial = 2 B_eq for same r. Using μ₀ = 4π×10⁻⁷ T·m/A, calculation involves r³ = (0.3)³ = 0.027 m³, so B = 10⁻⁷·m/r³ yields moment estimation. When cut transversely, each part has half the original magnetic moment. Given: m = 2.8 A m² . Each part: m' = (2.8/2) = 1.4 A m² . Substituting values gives 1.4 A m², which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.

Ref: NCERT > Physics Book > Magnetism and Matter > Magnetic Field Due to Bar Magnet - Axial and Equatorial

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Magnetic Field Lines, Bar Magnet and Dipole Moment

A bar magnet with original \( m = 1.4 \, \text{A m}^2 \) is cut along its length into two equal parts. What is \( m \) o

**Bar magnet properties** include dipole moment m = pole strength × separation, unit A·m², field lines emerge from north and enter south outside. Lines never cross, ensuring single valued B at any point, and pattern reflects dipole nature with symmetric loops around magnet. When cut along its length, each part typically has half the original magnetic moment in standard problems. Given: m = 1.4 A m² . Each part: m' = (1.4/2) = 0.7 A m² . Substituting values gives 0.7 A m², which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque rel

Ref: NCERT > Physics Book > Magnetism and Matter > Magnetic Field Lines, Bar Magnet and Dipole Moment

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