Practice question

**Axial versus equatorial** field comparison shows B_axial = 2 B_eq for same r. Using μ₀ = 4π×10⁻⁷ T·m/A, calculation involves r³ = (0.3)³ = 0.027 m³, so B = 10⁻⁷·m/r³ yields moment estimation. When cut transversely, each part has half the original magnetic moment. Given: m = 2.8 A m² . Each part: m' = (2.8/2) = 1.4 A m² . Substituting values gives 1.4 A m², which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.