What is the boiling point elevation of a solution containing 12 g of glucose (molar mass = 180 g/mol) in 600 g of water?
Moles of glucose = (12/180) ≈ 0.0667 mol . Molality = (0.0667/0.6) ≈ 0.111 mol/kg . Δ Tb = 0.52 × 0.111 ≈ 0.0577 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point