Practice question
Question
What is the boiling point elevation of a solution containing 12 g of glucose (molar mass = 180 g/mol) in 600 g of water? ( Kb = 0.52 K kg mol⁻¹ )
Explanation
Moles of glucose = (12/180) ≈ 0.0667 mol . Molality = (0.0667/0.6) ≈ 0.111 mol/kg . Δ Tb = 0.52 × 0.111 ≈ 0.0577 K .
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