12 public questions tagged with this topic.
Elimination (E₂) with alcoholic KOH favors tertiary halides due to stable alkene formation. (CH₃)3CBr reacts fastest.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
Elimination (E₂) of CH₃CH₂CHBrCH₂CH₂CH₃ with alcoholic KOH forms CH₃CH₂CH=CHCH₂CH₃ (3-hexene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
NaNH₂ (strong base) promotes E₂ elimination in CH₃CH₂CHClCH₂CH₃ , forming CH₃CH₂CH=CHCH₃ (2-pentene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
Alcoholic KOH (in methanol) promotes elimination (E₂) in CH₃CH₂CH₂Br , forming CH₃CH=CH₂ (propene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
CH₃CH=CHCH₃ (2-butene) with HCl forms CH₃CHClCH₂CH₃ , which eliminates HCl with alcoholic KOH to form 1-butene ( CH₃CH₂CH=CH₂ ).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in (CH₃)2CHCH₂Br , forming (CH₃)2C=CH₂ (2-methylpropene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Primary halides undergo elimination (E₂) slowest due to less stable transition states. CH₃CH₂CH₂Cl reacts slowest among the options.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in CH₃CH₂CH₂CHBrCH₃ , forming CH₃CH₂CH=CHCH₃ (2-pentene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in (CH₃)2CHCl , forming CH₂=CHCH₃ (propene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in CH₃CH₂Cl , forming CH₂=CH₂ (ethene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in CH₃CH₂CHClCH₃ , forming CH₃CH=CHCH₃ (2-butene) as the major product per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
