Practice question
Question
What is the product when CH₃CH₂CHClCH₂CH₃ reacts with NaNH₂ in liquid ammonia?
Explanation
NaNH₂ (strong base) promotes E₂ elimination in CH₃CH₂CHClCH₂CH₃ , forming CH₃CH₂CH=CHCH₃ (2-pentene) per Zaitsev's rule.
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