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MCQ

Question

What is the major alkene formed by dehydrohalogenation of CH₃CH(Br)CH₃ with alcoholic KOH ?

Choose one · Correct answer highlighted

CH₂=CH₂ CH₃CH=CH₂ Correct CH₃CH₂CH=CH₂ CH₂=CHCH₂CH₃

Dehydrohalogenation of 2-bromopropane with alcoholic KOH follows Zaitsev's rule, forming the more substituted alkene, CH₃CH=CH₂ (propene).

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