A spray tube (7cm2) has 35 holes of diameter 1.2mm. If the flow speed is 3.0m/min, what is the ejection speed?
A1v1 = A2v2, v1 = 3.0m/min = 0.05m/s, A1 = 7×10−4m2. Hole area: Ah = π(0.6×10−3)2, total A2 = 35×π×3.6×10−7≈3.958×10−5m2. v2 = 7×10−4×0.053.958×10−5≈0.884m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.9 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.