Practice question

A1v1 = A2v2, v1 = 2.7m/min = 0.045m/s, A1 = 5×10−4m2. Hole area: Ah = π(0.65×10−3)2, total A2 = 25×π×4.225×10−7≈3.318×10−5m2. v2 = 5×10−4×0.0453.318×10−5≈0.678m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.7 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.