A curve passes through (1, 1) such that the triangle formed by the coordinate axes and the tangent at any point of the c
We can see that using formula we get dy/dx = [(xy – 2) ± √(1 – xy)]/ x². Calculation gives this directly, check steps: apply rule, substitute values, simplify to get dy/dx = [(xy – 2) ± √(1 – xy)]/
Ref: NCERT Mathematics Class XII — Differential Equations
