Practice question
Question
A curve passes through (1, 1) such that the triangle formed by the coordinate axes and the tangent at any point of the curve is in the first quadrant and has its area equal to 2. What is the differential equation?
Explanation
We can see that using formula we get dy/dx = [(xy – 2) ± √(1 – xy)]/ x². Calculation gives this directly, check steps: apply rule, substitute values, simplify to get dy/dx = [(xy – 2) ± √(1 – xy)]/
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