Two small charged spheres with charges 5 × 10â»â· C and 7 × 10â»â· C are placed 50 cm apart in air. What is the fo
Given: Two small charged spheres with charges 5 × 10â»â· C and 7 × 10â»â· C are placed 50 cm apart in air. What is the force between them? These values define the system as per NCERT data. Formula: Using Coulomb’s law: F = k |q_1 q_2|/r². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: k = 9 × 10â¹ Nm²/C², q_1 = 5 × 10â»â· C, q_2 = 7 × 10â»â· C, r = 0.5 m . |q_1 q_2| = 5 × 7 × 10â»Â¹â´= 35 × 10â»Â¹â´ C² . r² = (0.5)² = 0.25 m² . F = 9 × 10⹠× frac35 × 10â»Â¹â´â°.25 = 9 × 10⹠× 1.4 × 10â»Â¹Â²= 0.0126 N . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.