Practice question

Given: Two charges q_1 = 2 μC and q_2 = -2 μC are 10 cm apart. What is the electric field at the midpoint between them? These values define the system as per NCERT data. Formula: E_1 = k q_1/r² (towards q_2 ), E_2 = k |q_2|/r² (towards q_2 ). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Midpoint is 5 cm (0.05 m) from each charge. . E_1 = 9 × 10⁹ × frac2 × 10⁻⁶(0.05)² = 7.2 × 10⁶ N/C, E_2 = 7.2 × 10⁶ N/C . Net E = E_1 + E_2 = 7.2 × 10⁶+ 7.2 × 10⁶= 1.44 × 10⁷ N/C (towards q_2 ). Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.