Skip to content

#compound analysis

4 public questions tagged with this topic.

In the Carius method, 0.6 g of a compound gave 0.717 g of AgI. What is the percentage of iodine?

Molar mass of AgI = 235 g/mol, I = 127 g/mol. Mass of I = (127/235) × 0.717 ≈ 0.387 g. Percentage = (0.387/0.6) × 100 ≈ 64.5%, which rounds to 64%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation