For Ag₂CrO₄(s) 2Ag+(aq) + CrO₄²⁻(aq) , Ksp = 1.1 × 10⁻¹² . In a 0.005 M AgNO₃ solution, what is [CrO₄²⁻] in a saturated
Ksp = [Ag+]²[CrO₄²⁻] = 1.1 × 10⁻¹² . [Ag+] = 0.005 + 2[CrO₄²⁻] ≈ 0.005 , (0.005)² [CrO₄²⁻] = 1.1 × 10⁻¹² , [CrO₄²⁻] = (1.1 × 10⁻¹²/2.5 × 10⁻⁵) = 4.4 × 10⁻⁸ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
