Practice question
Question
For Ag₂CrO₄(s) <=> 2Ag+(aq) + CrO₄²⁻(aq) , Ksp = 1.1 × 10⁻¹² . In a 0.005 M AgNO₃ solution, what is [CrO₄²⁻] in a saturated solution?
Explanation
Ksp = [Ag+]²[CrO₄²⁻] = 1.1 × 10⁻¹² . [Ag+] = 0.005 + 2[CrO₄²⁻] ≈ 0.005 , (0.005)² [CrO₄²⁻] = 1.1 × 10⁻¹² , [CrO₄²⁻] = (1.1 × 10⁻¹²/2.5 × 10⁻⁵) = 4.4 × 10⁻⁸ M .
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