Practice question
Question
For CaF₂ , if Ksp = 1.0 × 10⁻⁶ , what is the solubility of CaF₂ in mol/L?
Explanation
CaF₂ <=> Ca²⁺ + 2F⁻ , Ksp = [Ca²⁺][F⁻]² = S (2S)² = 4S³ = 1.0 × 10⁻⁶ . Solving, S³ = 2.5 × 10⁻⁷ , S ≈ 6.3 × 10⁻³ .
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