We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy1 public question tagged with this topic.
For Δ ng = 2 - 2 = 0 , RT = 8.314 × 298 × 10⁻³ = 2.4776 kJ . Using Δ H = Δ U + Δ ng RT , Δ U = -103.00 - 0 = -103.00 kJ/mol .
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Third Law of Thermodynamics and Applications
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
