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Practice question

MCQ

Question

For CH₄(g) + Cl₂(g) → CH₃Cl(g) + HCl(g) , Δ H = -103.00 kJ/mol at 298 K. What is Δ U ? ( R = 8.314 J/mol·K )

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Explanation

For Δ ng = 2 - 2 = 0 , RT = 8.314 × 298 × 10⁻³ = 2.4776 kJ . Using Δ H = Δ U + Δ ng RT , Δ U = -103.00 - 0 = -103.00 kJ/mol .

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