Calculate Δ H for C(s) + H₂O(g) → CO(g) + H₂(g) given: C(s) + O₂(g) → CO₂(g), Δ H = -393.5 kJ/mol; CO(g) + (1/2)O₂(g) →

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Calculate Δ H for C(s) + H₂O(g) → CO(g) + H₂(g) given: C(s) + O₂(g) → CO₂(g), Δ H = -393.5 kJ/mol; CO(g) + (1/2)O₂(g) → CO₂(g), Δ H = -283 kJ/mol; H₂O(g) → H₂(g) + (1/2)O₂(g), Δ H = 241.8 kJ/mol.

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-131.3 kJ/mol 131.3 kJ/mol Correct -434.8 kJ/mol 434.8 kJ/mol

Reverse second: Δ H = 283 kJ. Add third: Δ H = 241.8 kJ. Subtract first: Δ H = 283 + 241.8 - 393.5 = 131.3 kJ/mol.

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