63 public questions tagged with this topic.
α = τI = 168 = 2rad/s2. Δω = αt = 2×3 = 6rad/s. ω = ω0+Δω = 2+6 = 8rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
α = τI = 105 = 2rad/s2. Δω = αt = 2×5 = 10rad/s. ω = ω0+Δω = 3+10 = 13rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 13 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
If the net external torque is zero (dLdt = τ = 0), angular momentum is conserved, and for a fixed moment of inertia, angular velocity remains constant. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It remains constant. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 3×(0.4)2 = 0.48kg m2. K = 12Iω2 = 12×0.48×(5)2 = 0.24×25 = 6J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.0 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 25MR2 = 25×6×(0.4)2 = 0.384kg m2. ω = LI = 11.520.384 = 30rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 30 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
α = τI = 126 = 2rad/s2. Δω = αt = 2×3 = 6rad/s. ω = ω0+Δω = 3+6 = 9rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 25MR2 = 25×5×(0.2)2 = 0.08kg m2. ω = LI = 80.08 = 100rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 100 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
L = Iω. For a sphere: I = 25MR2 = 25×5×(0.3)2 = 0.18kg m2. ω = LI = 90.18 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
For rolling without slipping: v = ωr. v = 5m/s, r = 0.1m. ω = vr = 50.1 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
For a rigid body rotating about a fixed axis, all particles have the same angular velocity, regardless of their distance from the axis, as it’s a property of the body’s rotation as a whole.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 25MR2 = 25×3×(0.4)2 = 0.192kg m2. ω = LI = 120.192≈62.5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 62.5 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
The linear velocity v of a particle in rotational motion is related to angular velocity ω by v = ωr, where r is the perpendicular distance from the axis. As per NCERT, applying relevant law/formula with correct units and sign convention leads to v\=ωr. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
