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Question

A rod rotates at 10 rad/s in a 0.5 T field. If the length from the axis to the tip is 0.6 m, what is
the emf induced?

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Explanation

**Energy stored in inductor** U =½ L I², L inductance, I current, energy in magnetic field, density u = B²/(2μ₀), B=μ₀ n I inside solenoid, U = (B²/2μ₀)×volume, illustrating equivalence of circuit and field energy. ε = (1/2) B ω R² . ε = (1/2) × 0.5 × 10 × (0.6)² = 0.9 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I², result 0.9 V follows, reflecting Faraday's law and Lenz's opposition.

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