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#analytical chemistry

19 public questions tagged with this topic.

In the Carius method, 0.25 g of a compound gave 0.574 g of AgBr . What is the percentage of bromine? (Atomic masses: Ag

Given: In the Carius method, 0.25 g of a compound gave 0.574 g of AgBr . What is the percentage of bromine? (Atomic masses: Ag = 108, Br = 80) These values define the system as per NCERT data. Formula: Molar mass of AgBr = 108 + 80 = 188 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of Br = 80 × 0.574/188 = 0.244 g. Percentage = 0.244 × 100/0.25 = 97.6% . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

In the Carius method, which reagent is used to precipitate sulphur as BaSOâ‚„ ?

Sulphur is oxidized to Hâ‚‚SOâ‚„, which reacts with BaClâ‚‚ to form a white precipitate of BaSOâ‚„ in the Carius method. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Which method is used to detect phosphorus in an organic compound by converting it to phosphate?

In the Carius method, phosphorus is oxidized with HNO₃ to form H₃PO₄, which is precipitated as ammonium phosphomolybdate. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Organic Chemistry - Basic Principles, Hydrocarbons and Reaction Mechanisms, Topic: Nomenclature, isomerism and reaction types.

In Kjeldahl’s method, which acid is used to digest the organic compound?

H₂SO₄ is used to digest the organic compound, converting nitrogen to (NH₄)2SO₄ in Kjeldahl’s method. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Chemical Bonding (Latest NCERT 2026-27), Topic: Hybridization of nitrogen in CH₃NH₂, sp³ hybridization and pyramidal geometry

In Kjeldahl’s method, which base is used to liberate ammonia from the digested sample?

NaOH is added to the digested sample ( (NH₄)2SO₄ ) to liberate NH₃, which is then distilled and titrated. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Which technique is least effective for separating a mixture of two liquids with boiling points of 110°C and 150°C, one o

Sublimation is for solids, not liquids. Simple distillation (40°C difference) or differential extraction (solubility) would work, but sublimation is irrelevant.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Isomerism - Stereoisomerism - Geometrical and Optical Isomerism

In Kjeldahl’s method, 0.42 g of a compound produced ammonia that neutralized 15 mL of 0.2 M H₂SO₄. What is the percentag

Moles of H₂SO₄ = 0.015 × 0.2 = 0.003. Moles of NH₃ = 0.006 (2H per H₂SO₄). Mass of N = 0.006 × 14 = 0.084 g. Percentage = (0.084/0.42) × 100 = 20%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Isomerism - Stereoisomerism - Geometrical and Optical Isomerism