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Practice question

Question

In the Carius method, 0.25 g of a compound gave 0.574 g of AgBr . What is the percentage of bromine? (Atomic masses: Ag = 108, Br = 80)

Options

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Explanation

Given: In the Carius method, 0.25 g of a compound gave 0.574 g of AgBr . What is the percentage of bromine? (Atomic masses: Ag = 108, Br = 80) These values define the system as per NCERT data. Formula: Molar mass of AgBr = 108 + 80 = 188 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of Br = 80 × 0.574/188 = 0.244 g. Percentage = 0.244 × 100/0.25 = 97.6% . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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