#aluminium wire

Stress, Strain and Hooke's Law

An aluminium wire of length 1.8m and cross-sectional area 2×10−6m2 is stretched by a force producing a strain of 2×10−4.

Young's modulus: Y = StressStrain. Stress: Stress = Y×Strain = 7×1010×2×10−4 = 1.4×107N/m2. Force: F = Stress×A = 1.4×107×2×10−6 = 28N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 28N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Shear Modulus and Rigidity

An aluminium wire of length 1.7m and cross-sectional area 2×10−6m2 is stretched by 0.34mm. If the Young's modulus of alu

Young's modulus: Y = FLAΔL. Rearrange: F = YAΔLL. Substitute: ΔL = 0.34×10−3m. F = 7×1010×2×10−6×0.34×10−31.7 = 47.61.7≈28N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 28N. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Shear Modulus and Rigidity

An aluminium wire of length 2.5m and cross-sectional area 1.5×10−6m2 is stretched by a force of 150N. If the Young's mod

Stress: Stress = FA = 1501.5×10−6 = 1×108N/m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1×108N/m2. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Young's Modulus and Elasticity

An aluminium wire of length 2.0m and cross-sectional area 1.5×10−6m2 is stretched by a force of 150N. If the Young's mod

Young's modulus: Y = FLAΔL. Rearrange: ΔL = FLAY. Substitute: ΔL = 150×2.01.5×10−6×7×1010 = 3001.05×105≈2.86×10−3m = 2.86mm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.86mm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Stress, Strain and Hooke's Law

An aluminium wire of length 2.3m and cross-sectional area 1.5×10−6m2 is stretched by a force producing a stress of 2×107

Young's modulus: Y = StressStrain. Strain: Strain = StressY = 2×1077×1010≈2.86×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.86×10−4. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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