Practice question
Question
An aluminium wire of length 2.3m and cross-sectional area 1.5×10−6m2 is stretched by a force producing a stress of 2×107N/m2. If the Young's modulus of aluminium is 7×1010N/m2, what is the strain?
Explanation
Young's modulus: Y = StressStrain. Strain: Strain = StressY = 2×1077×1010≈2.86×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.86×10−4. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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