Practice question

**Charles' law** V₁/T₁ = V₂/T₂ at constant pressure, volume proportional to absolute temperature (K), Gay-Lussac P₁/T₁ = P₂/T₂ at constant volume, Boyle's law P₁V₁ = P₂V₂ at constant temperature, combined ideal gas law P V = n R T, R=8.314 J/mol·K. For V₁=24 L T₁=300 K T₂=600 K, V₂= V₁ T₂/T₁=48 L, volume doubles when T doubles at constant P. Boyle’s law: P₁ V₁ = P₂ V₂.P₁ = 1 atm, V₁ = 10 litres, V₂ = 5 litres.P₂ = (P₁ V₁)/(V₂) = (1 × 10)/(5) = 2 atm . Substituting values gives 2.0 atm, which matches expected kinetic theory result, confirming mean free path λ