Practice question

Given: A 45 kg man in a lift accelerating downward at 1.5 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² ) Formula: Net force: N - mg = ma, where a = -1.5 m/s². Substitution & Calculation: Scale reads normal force. . N - 45 × 10 = 45 × (-1.5) . N - 450 = -67.5 Rightarrow N = 382.5 N . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.