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#lift

2 public questions tagged with this topic.

A 45 kg man in a lift accelerating downward at 1.5 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² )

Given: A 45 kg man in a lift accelerating downward at 1.5 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² ) Formula: Net force: N - mg = ma, where a = -1.5 m/s². Substitution & Calculation: Scale reads normal force. . N - 45 × 10 = 45 × (-1.5) . N - 450 = -67.5 Rightarrow N = 382.5 N . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

Why does blowing over a piece of paper lift it upwards?

Bernoulli’s principle states that faster airflow above the paper reduces pressure, while slower air below maintains higher pressure, creating an upward lift due to the pressure difference. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Due to lower pressure above from faster airflow. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.