Skip to content

#apparent weight

3 public questions tagged with this topic.

A 40 kg man in a lift accelerating downward at 3 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² )

Given: A 40 kg man in a lift accelerating downward at 3 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: Net force: N - mg = ma, where a = -3 m/s². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: The scale shows the normal force. . N - 40 × 10 = 40 × (-3) . N - 400 = -120 Rightarrow N = 280 N . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per N

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

A 45 kg man in a lift accelerating downward at 1.5 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² )

Given: A 45 kg man in a lift accelerating downward at 1.5 m/s² stands on a scale. What is the reading? (Take g = 10 m/s² ) Formula: Net force: N - mg = ma, where a = -1.5 m/s². Substitution & Calculation: Scale reads normal force. . N - 45 × 10 = 45 × (-1.5) . N - 450 = -67.5 Rightarrow N = 382.5 N . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.