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Practice question

MCQ

Question

What is the emf of the cell Co(s) | Co²⁺(0.02 M) || H⁺(0.01 M) | H₂(g)(1 bar) | Pt(s) at 298 K? (Given: E°Co²⁺/Co = -0.28 V , E°H⁺/H_₂ = 0.00 V )

Options

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Explanation

E°cell = 0.00 - (-0.28) = 0.28 V . Ecell = 0.28 - (0.059/2) log (0.02/0.01²) = 0.28 - 0.07375 = 0.20625 V .

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