Practice question

MCQ

Question

The resistance of a conductivity cell with 0.001 M KCl solution is 1500 Ω, and its conductivity is 0.146 × 10⁻³ S cm⁻¹. What is the cell constant?

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Choose one · Correct answer highlighted

0.146 cm⁻¹ 1.500 cm⁻¹ 0.219 cm⁻¹ Correct 0.073 cm⁻¹

Explanation

kappa = (cell constant/R) , 0.146 × 10⁻³ = (cell constant/1500) , cell constant = 0.219 cm⁻¹.

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