#conductivity cell

Nernst Equation and Gibbs Energy and Equilibrium Constant

The resistance of a conductivity cell with 0.01 M NaCl solution is 250 Ω, and its conductivity is 0.0012 S cm⁻¹. What is

kappa = (cell constant/R) , 0.0012 = (cell constant/250) , cell constant = 0.3 cm⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant

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Nernst Equation and Gibbs Energy and Equilibrium Constant

What is the cell constant of a conductivity cell if the resistance of a 0.01 M KCl solution is 200 Ω and its conductivit

kappa = (cell constant/R) , 0.00141 = (cell constant/200) , cell constant = 0.282 cm⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant

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Nernst Equation and Gibbs Energy and Equilibrium Constant

The resistance of a conductivity cell with 0.001 M KCl solution is 1500 Ω, and its conductivity is 0.146 × 10⁻³ S cm⁻¹.

kappa = (cell constant/R) , 0.146 × 10⁻³ = (cell constant/1500) , cell constant = 0.219 cm⁻¹.

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant

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Electrolytic Cells and Electrolysis and Faraday's Laws

The resistance of a conductivity cell with 0.02 M NaCl solution is 500 Ω, and its conductivity is 0.0024 S cm⁻¹. What is

kappa = (cell constant/R) , 0.0024 = (cell constant/500) , cell constant = 1.2 cm⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrolytic Cells and Electrolysis and Faraday's Laws

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Electrochemical Cells - Galvanic Cells and Electrode Potential

The resistance of a conductivity cell with 0.02 M KCl solution is 400 Ω, and its conductivity is 0.0025 S cm⁻¹. What is

kappa = (cell constant/R) , 0.0025 = (cell constant/400) , cell constant = 1.0 cm⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrochemical Cells - Galvanic Cells and Electrode Potential

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with cell constant 0.5 cm⁻¹ shows a resistance of 200 Ω with a 0.02 M KCl solution. What is the mola

kappa = (cell constant/R) = (0.5/200) = 0.0025 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0025 × 1000/0.02) = 125 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with cell constant 0.5 cm⁻¹ shows a resistance of 200 Ω with a 0.02 M KCl solution. What is the mola

kappa = (cell constant/R) = (0.5/200) = 0.0025 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0025 × 1000/0.02) = 125 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with cell constant 0.4 cm⁻¹ shows a resistance of 250 Ω with a 0.02 M NaCl solution. What is the mol

kappa = (cell constant/R) = (0.4/250) = 0.0016 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0016 × 1000/0.02) = 80 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with cell constant 0.4 cm⁻¹ shows a resistance of 250 Ω with a 0.02 M NaCl solution. What is the mol

kappa = (cell constant/R) = (0.4/250) = 0.0016 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0016 × 1000/0.02) = 80 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with a 0.015 M KNO₃ solution has a resistance of 300 Ω and a cell constant of 0.75 cm⁻¹. What is the

kappa = (cell constant/R) = (0.75/300) = 0.0025 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0025 × 1000/0.015) = 166.67 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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