Practice question
Question
The resistance of a conductivity cell with 0.02 M NaCl solution is 500 Ω, and its conductivity is 0.0024 S cm⁻¹. What is the cell constant?
Explanation
kappa = (cell constant/R) , 0.0024 = (cell constant/500) , cell constant = 1.2 cm⁻¹ .
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