Practice question

MCQ

Question

What is the cell constant of a conductivity cell if the resistance of a 0.01 M KCl solution is 200 Ω and its conductivity is 0.00141 S cm⁻¹?

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0.141 cm⁻¹ 0.282 cm⁻¹ Correct 1.41 cm⁻¹ 2.82 cm⁻¹

Explanation

kappa = (cell constant/R) , 0.00141 = (cell constant/200) , cell constant = 0.282 cm⁻¹ .

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