Practice question
Question
The resistance of a conductivity cell with 0.01 M NaCl solution is 250 Ω, and its conductivity is 0.0012 S cm⁻¹. What is the cell constant?
Explanation
kappa = (cell constant/R) , 0.0012 = (cell constant/250) , cell constant = 0.3 cm⁻¹ .
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.