Practice question
Question
A cell Cd(s) | Cd²⁺(0.005 M) || Br₂(l) | Br⁻(0.01 M) | Pt(s) operates at 298 K. What is the cell potential? (Given: E°Cd²⁺/Cd = -0.40 V , E°Br_₂/Br⁻ = 1.07 V )
Explanation
E°cell = 1.07 - (-0.40) = 1.47 V . Ecell = 1.47 - (0.059/2) log ([Cd²⁺][Br⁻]²/1) = 1.47 - 0.0295 log (0.005 × 0.0001) = 1.47 + 0.103 = 1.573 V .
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