Practice question
Question
What is the collision frequency of a gas molecule with a mean free path of 1.2 × 10⁻⁷ m and average speed of 480 m/s?
Explanation
**Gas laws** Boyle, Charles, Gay-Lussac are special cases of ideal gas equation, for constant pressure volume-temperature relation V ∝ T, for constant temperature pressure-volume inverse, for constant volume pressure-temperature direct, enabling calculation of new volume from temperature ratio. Collision frequency = ()/(l).(480)/(1.2 × 10⁻⁷) = 4.0 × 10⁹ s⁻¹. Substituting values gives 4.0 × 10⁹ s⁻¹, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V = n R T and v_rms = √(3 R T/M) relations.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.