Practice question
Question
The majority carriers in an n-type semiconductor are:
Explanation
**Number of carriers** from doping: Ge crystal 4×10²⁸ atoms/m³ doped 2 ppm trivalent gives acceptor atoms 8×10²² m⁻³, holes ≈ that, for 1.5 ppm 6×10²² m⁻³, for 0.5 ppm pentavalent Si 5×10²⁸ atoms/m³ gives 2.5×10²² donors/m³. Acceptor atom effectively negative when accepts electron, donor positive when donates, but crystal neutral. In an n-type semiconductor, pentavalent doping increases the number of conduction electrons, making them the majority carriers, while holes are minority carriers ( n_e gg n_h ). Substituting values gives Electrons, which matches expected behaviour for this semiconductor device configuration, confirming doping, depletion and rectifier principles.
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