Skip to content

Question

The majority carriers in an n-type semiconductor are:

Options

Choose one · Correct answer highlighted

Explanation

**Number of carriers** from doping: Ge crystal 4×10²⁸ atoms/m³ doped 2 ppm trivalent gives acceptor atoms 8×10²² m⁻³, holes ≈ that, for 1.5 ppm 6×10²² m⁻³, for 0.5 ppm pentavalent Si 5×10²⁸ atoms/m³ gives 2.5×10²² donors/m³. Acceptor atom effectively negative when accepts electron, donor positive when donates, but crystal neutral. In an n-type semiconductor, pentavalent doping increases the number of conduction electrons, making them the majority carriers, while holes are minority carriers ( n_e gg n_h ). Substituting values gives Electrons, which matches expected behaviour for this semiconductor device configuration, confirming doping, depletion and rectifier principles.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.