Practice question

MCQ

Question

The Ksp of PbCl₂ is 1.6 × 10⁻⁵ . What is its solubility in pure water in mol/L?

Options

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1.6 × 10⁻² Correct 2.0 × 10⁻² 4.0 × 10⁻³ 8.0 × 10⁻³

Explanation

For PbCl₂ <=> Pb²⁺ + 2Cl⁻ , Ksp = [Pb²⁺][Cl⁻]² = S (2S)² = 4S³ = 1.6 × 10⁻⁵ . Solving, S³ = 4 × 10⁻⁶ , S = (4 × 10⁻⁶)¹/³ ≈ 1.6 × 10⁻² .

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