Practice question
Question
The Ksp of Mg(OH)2 is 1.8 × 10⁻¹¹ . What is the solubility of Mg(OH)2 in pure water in mol/L?
Explanation
For Mg(OH)2 <=> Mg²⁺ + 2OH- , Ksp = [Mg²⁺][OH-]² = S (2S)² = 4S³ = 1.8 × 10⁻¹¹ . Solving, S³ = (1.8 × 10⁻¹¹/4) = 4.5 × 10⁻¹² , S ≈ 1.65 × 10⁻⁴ .
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.