#Mg(OH)2

The Ksp of Mg(OH)2 is 1.8 × 10⁻¹¹ . What is the solubility of Mg(OH)2 in pure water in mol/L?

For Mg(OH)2 Mg²⁺ + 2OH- , Ksp = [Mg²⁺][OH-]² = S (2S)² = 4S³ = 1.8 × 10⁻¹¹ . Solving, S³ = (1.8 × 10⁻¹¹/4) = 4.5 × 10⁻¹² , S ≈ 1.65 × 10⁻⁴ .

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect